ABCD is a quadrilateral such that angle D is 90°. A circle C(0,r) touches the sides AB, BC, CD and DA at P,Q,R and S respectively. If BC=38cm, CD=25cm and BP=27cm, then find r
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Properties used:
A tangent is perpendicular to the radius.
The tangent segments to a circle from same external point are equal.
Answer:
BP=27
therefore, BQ=27 (property 2)
so QC=38-27=11
therefore, CR=11
so RD=25-11=14
in quad. ORDS
ang.D=90
ang.R=90 (prop. 1)
OR=OS
therefore,ORDS is a square
therefore,
OS=RD
radius=RD
r=14
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