ABCD is a quadrilateral such that diagonal AC bisects the angle a and c prove that AB =AD and CB=CD
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In triangle ABC and ADC
AC=AC (common)
angle 1= angle 2. {given }
ang.3 = ang.4 {given}
By ASA ∆ are congurent
So, AB=AD
CB=CD {C.P.C.T. }
AC=AC (common)
angle 1= angle 2. {given }
ang.3 = ang.4 {given}
By ASA ∆ are congurent
So, AB=AD
CB=CD {C.P.C.T. }
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Answer:
Explanation:
Given :- BAC = DAC
BCA = DCA
TO PROVE :- AB = AD
CB = CD
PROOF :- IN TRIANGLE ABC AND ADC
BAC = DAC
BCA = DCA
AC = AC
HENCE., TRIANGLE ABC CONGRUENT TRIANGLE ADC
IMPLIES THAT., AB = AD
CB = CD
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