ABCD is a quadrilateral, two diagonals AC and BD intersect at point O The mid point of diagonal AC and BD are P and Q respectively, it M is the midpint of PQ show that
BA + BD = 2BD
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Class 9
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The diagonal AC and BD of a parallelogram ABCD intersect at O. If P is the midpoint of AD, prove that PQ∥AB
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It is given that,
ABCD is a parallelogram in which diagonals AC and BD intersect each other at int O,P is the midpoint of AD
Join OP
To prove: PQ∣∣AB
Proof:
We know that,
The diagonals of parallelogram bisect each other
⇒BO=OD
⇒O is the midpoint of BD
In △ABD
P and O is the mid point of AB and BD
⇒PO∥AB[ Converse of midpoint theorem
⇒PQ∥AB
Hence, proved
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