ABCD is a quadrilateral .
What is the value of Cos1/2(A+C) + Cos1/2(B+D) ?
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Answer:
Let ABCD be the quad.
So,A+B+C+D=360 degree (angle sum property of a quad.)
Now,cos1/2(A+C)+cos1/2(B+D)
=cos1/2(A+C+B+D)
=cos1/2×360
=cos180
=(cos90)2
=0×2
=0(answer).
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