ABCD is a quadrilateral whose diagonals intersect each other at the point O such that a is equal to o b o b is equal to OD if angle abc is equal to 30 degree then the measure of angle b is equal to
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Given, OA=OB
∴∠OAB=∠OBA (opp. angle of equal side is equal)
Thus, ∠OAB=∠OBA=30
∘
In ΔOAB
∠OAB+∠AOB+∠OBA=180
∘
(Angle Sum Property)
30
∘
+∠AOB+30
∘
=180
∘
∠AOB=120
∘
As DOB is a straight line
∴∠DOA=180
∘
(Linear Pair)
∠DOA+∠AOB=180
∘
∠DOA=60
∘
Now, in ΔAOD
∠ODA+∠DOA+∠DAO180
∘
2∠ODA+60
∘
=180
∘
[∵∠ODA=∠DOAasOA=OD]
2∠ODA=120
∘
∠ODA=60
∘
Hence, option 'C' is correct.
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