ABCD is a quadrilateral whose sides are 40m,42m,30m,32m . Then find the area of quadrilateral...
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Given the sides a, b, c and d of a quadrilateral we can use the formulae below to get the area.
A = √(s- a) (s - b) (s - c) (s - d)
s = (a + b + c + d) /2
s = (40 + 42 + 32 +30) / 2 = 144/2 = 72
Substituting in the formula :
A =√(72 - 40)(72 - 42)(72 - 32)(72 - 30)
A = √(32 × 30 × 42 × 40) = √1612800
A =√1612800 =1269.96m²
A = √(s- a) (s - b) (s - c) (s - d)
s = (a + b + c + d) /2
s = (40 + 42 + 32 +30) / 2 = 144/2 = 72
Substituting in the formula :
A =√(72 - 40)(72 - 42)(72 - 32)(72 - 30)
A = √(32 × 30 × 42 × 40) = √1612800
A =√1612800 =1269.96m²
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Solution :-
Ancient Indian Mathematician (CE 598 - 665) Brahmagupta gave the following formula for finding the area of a quadrilateral, which does not require the angle measurement. Only length of four sides is sufficient.
Area = √(s - a)(s - b)(s - c)(s - d)
s = (a + b + c + d)/2
a, b, c and d are four sides respectively.
⇒ (40 + 42 + 30 + 32)/2
⇒ 144/2
s = 72 m
Area = √(72 - 40)(72 - 42)(72 - 30)(72 - 32)
⇒ √32*30*42*40
⇒ √1612800
⇒ Area = 1269.96 m²
Answer.
Ancient Indian Mathematician (CE 598 - 665) Brahmagupta gave the following formula for finding the area of a quadrilateral, which does not require the angle measurement. Only length of four sides is sufficient.
Area = √(s - a)(s - b)(s - c)(s - d)
s = (a + b + c + d)/2
a, b, c and d are four sides respectively.
⇒ (40 + 42 + 30 + 32)/2
⇒ 144/2
s = 72 m
Area = √(72 - 40)(72 - 42)(72 - 30)(72 - 32)
⇒ √32*30*42*40
⇒ √1612800
⇒ Area = 1269.96 m²
Answer.
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