Question

abcd is a quadrilateral with angle a = angle c and angle b = angle d. If angle a is twice angle b, find the measure of each angle​

Answer 1

if angle is twice the angle b then we can say that angle A=2angle B

A+B+C+D=360 (ASP of the quad)

B+2B+B+2B=360 (B=C and B=2A)

6B=360

B= 360/6

B=60

B=D=60

A=2B=2×60=120

A=C=120

Answer 2

Given : ABCD is a quadrilateral

$\angle A = \angle C...(1) \\\\\angle B = \angle D...(2) \\\\\angle A= 2\angle B ..(3)$

To find : the measure of each angle​

Solution:

we know that sum of all the angles of the quadrilateral is 360 degrees

thus

$\angle A +\angle B + \angle C + \angle D = 360^\circ$

from equation 1 ,2,and 3

2B +B +2B +B = 360

6B = 360

B = 60°

therefore

$\angle B = \angle C = 60^\circ \\\\\angle A = \angle C = 2\angle B = 2\times 60 = 120^\circ$

hence , all the angle are  60°,120°,60°,120°

#Learn more :

https://brainly.in/question/2631240