ABCD is a quadrilateral with angle BAD=40
AB is extended to E and angle EBC=30
AB=AD and BC=BD
Calculate angle BCD
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akku1877:
this question is from which class ? can yu tell me please
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Answered by
6
here AB=AD
so ANGLE ABD=ADB=x
x+x+40=180
2x=140
x=70
so CBD=180-30-70=80
and BD=BC
so angle BDC=BCD=y
and in∆BCD
y+y+80=180
2y=100
y=50
so ANGLE ABD=ADB=x
x+x+40=180
2x=140
x=70
so CBD=180-30-70=80
and BD=BC
so angle BDC=BCD=y
and in∆BCD
y+y+80=180
2y=100
y=50
Answered by
0
here's your answer reasons given in brackets in short
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