ABCD is a quadrilateral with <A=<C and
<B=<D. If <A is twice <B, find the measure
of each angle.
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Given:
ABCD is a quad. in which <A=<C & <B=<D
<A = 2<B
Solution:
Since, <A=<C & <B=<D.
Therefore quad. ABCD is a llgm.
Now, we know that the some of adjacent angles of a llgm is 180°.
So,. <A + < B = 180°. --------------(i)
2<B + < B = 180°
3<B = 180°
<B = 60°
Now, <D = <B = 60°
<A = <C = 180°- 60° = 120°. [from (i)]
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