Question

ABCD is a quadrilatral. Prove that cos (A+B)/4=sin (C+D)/4

Answer 1

Answer:hence Proved

Step-by-step explanation:In Quadrilateral , A + B + C + D = 360 ° A + B = 360 ° - C + D Dividing both sides by 4 , we get A + B 4 = 360 ° - C + D 4 A + B 4 = 90 ° - C + D 4 Taking cos on both sides , we get cos A + B 4 = cos C + D 4 cos A + B 4 = sin C + D 4 Since cos 90 -C+D4cosA+B4=sinC+D4

Since cos90-x=sin x.

Hence Proved...........

Please mark as the Brainliest Answer..............

Answer 2

Answer:

answer for the given problem is given