Question

abcd is a quadrilatrel AB||CD

Answer 1

here is the answer to your question

Answer 2

w.k t

∠a=∠c=80°(ab║cd and alternate angles are equal)

∠b=∠c=84°(ab║cd znd alternate angles are equal)                                                        ∠cda=1/2 ∠cdp      so,84/2 =42° and similarly ∠dcb=1/2∠dcp and 80/2=40

in triangle pdc       w.k.t in triangle all angles are equal to 180°

so ∠cda+∠dcp+dpc=180°                                                                                                 =42+40+∠dpc=180°                                                                                                                      =∠dpc=180-82     and ∠DPC=92°