Question

abcd is a rahombus with each side of length 10cm and one diagonal of length 10 cm fimd the area od rhombus​

Answer 1

Given:

• Diagonals of a rhombus bisect each other at right angles.

Prove:

• Let ABCD be the rhombus, Diagonal AC= 16 cm and side AB = 10 cm.

• In right triangle AOB, AB = 10 cm, AO = 8 cm

By Pythagoras theorem, AB2 = AO2 + BO2

• ➽(10)2 = (8)2 + BO2
• ➽BO2 = (10)2 – (8)2
• ➽BO = 6 cm
• ➽Diagonal BD = 2 x 6 = 12 cm

area of rhombus = 1/2× ( product of diagonals)

• = 1/2 × 16 × 12
• = 96cm^2

Hence length of other diagonal = 12 cm; Area of rhombus = 96 cm2