Question

□ABCD is a rectangle, AB=10 cm ,BC = 24 cm then find AC.​

Answer 1

Step-by-step explanation:

ABCD is a rectangle AB = 7cm , BC = 24 cm, find AC .

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Answer᎓

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Formula for Diagonal:

\bold{\boxed{ D = \sqrt{ {(l)}^{2} + {(b)}^{2} }}}

D=

(l)

2

+(b)

2

=>Here ,length is BC =24cm

Breadth is AB =7cm

= > D = \sqrt{ {(24)}^{2} + {(7)}^{2} }=>D=

(24)

2

+(7)

2

= > D= \sqrt{576 + 49}=>D=

576+49

= > D = \sqrt{625} = 25cm=>D=

625

=25cm

Therefore, Diagonal of a rectangle(AC) is 25 cm.

AC=25CM

Area of Rectangle =Length × breadth

= 24 \times 7 = {168cm}^{2}=24×7=168cm

2

Answer 2

Step-by-step explanation:

as it is rectengle the opposite sides of a rectangle is always equal so opposite of AC there will be BC

So AC = BC = 24 CM IS THE ANS ...HOPE IT HELPS 5 TKX = IB