ABCD is a rectangle AB= 11cm
BC= 60cm find AC.
Answers
Answered by
6
This is the correct answer .
Given ABCD is a rectangle.
AB=11cm
BC=60cm
To find AC
Solution= draw a line AC
We can apply Pythagorus theorem
(H)^2=(p)^2+(b)^2
= 11^2+60^2
121+3600
3721
3721=(61)^2
H=61
AC=61cm ANSWER
Hope this helps you .
Given ABCD is a rectangle.
AB=11cm
BC=60cm
To find AC
Solution= draw a line AC
We can apply Pythagorus theorem
(H)^2=(p)^2+(b)^2
= 11^2+60^2
121+3600
3721
3721=(61)^2
H=61
AC=61cm ANSWER
Hope this helps you .
Answered by
14
ABCD is a rectangle. In which AB = 11 cm and BC = 60 cm. Then, find AC.
Length of rectangle (BC) = 60 cm
Breadth of rectangle (AB) = 11 cm
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Length to be found = AC ( diagonal of rectangle )
Here, we will apply , Pythagoras property
Let, length of AC = x
AB² + BC² = AC²
11² + 60² = x²
121 + 3600 = x²
3721 = x²
√3721 = x
61 = x
So, the value of x or diagonal of rectangle that is AC = 61 cm.
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