Question

ABCD is a rectangle AB= 11cm
BC= 60cm find AC. ​

Answer 1

This is the correct answer .
Given ABCD is a rectangle.
AB=11cm
BC=60cm
To find AC
Solution= draw a line AC
We can apply Pythagorus theorem
(H)^2=(p)^2+(b)^2
= 11^2+60^2
121+3600
3721
3721=(61)^2
H=61

AC=61cm ANSWER

Hope this helps you .

Answer 2

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ABCD is a rectangle. In which AB = 11 cm and BC = 60 cm. Then, find AC.

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Length of rectangle (BC) = 60 cm

Breadth of rectangle (AB) = 11 cm

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Length to be found = AC ( diagonal of rectangle )

Here, we will apply , Pythagoras property

Let, length of AC = x

AB² + BC² = AC²

11² + 60² = x²

121 + 3600 = x²

3721 = x²

√3721 = x

61 = x

So, the value of x or diagonal of rectangle that is AC = 61 cm.

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