Question

ABCD is a rectangle AB = 7cm , BC = 24 cm, find AC .​

Answer 1

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ABCD is a rectangle AB = 7cm , BC = 24 cm, find AC .

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Formula for Diagonal:

$\bold{\boxed{ D = \sqrt{ {(l)}^{2} + {(b)}^{2} }}}$

=>Here ,length is BC =24cm

Breadth is AB =7cm

$= > D = \sqrt{ {(24)}^{2} + {(7)}^{2} }$

$= > D= \sqrt{576 + 49}$

$= > D = \sqrt{625} = 25cm$

Therefore, Diagonal of a rectangle(AC) is 25 cm.

AC=25CM

Area of Rectangle =Length × breadth

$= 24 \times 7 = {168cm}^{2}$

$\huge\mathcal{Learn\:More:}$

• A rectangle is a type of Quadrilateral

• Rectangle having four sides two are length and two are breadth.e.g=>AB=BC=CD=AD
• Diagonal of a rectangle are equal in Length.e.g=>AC=BD
• Opposite sides are equal and parallel to each other.AB=CD
• The sum of all interior angles of a Rectangle is equal to 360°.

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Answer 2

hope it's helpful 4 u......

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