Abcd is a rectangle ab=8 cm ad =20 cm.If a, b and c are inradius of incircle of ∆bap, ∆bpc and ∆cpd. Where d is any point on ad such that angle bpc is 90°find a+ b+c
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ABCD is a rectangle.
So all angles will be right angles
so,a=90°
b=90°
c=90°
so,a+b+c=90+90+90=270°
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