Question

abcd is a rectangle and bd is one of its diagnol. If ar (triangle and) =8cm find ar(triangle BDC)
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Answer 1

Answer:

Given that ABCD is a trapezium with AB || DC and Diagonal AC and BD intersect each other at O.

To prove: Area (AOD) = Area (BOC)

Proof: ΔADC and ΔBDC are on the same base DC and between same parallel AB and DC.

∴Area (ΔADC) = Area (ΔBDC) [triangles on the same base and between same parallel are equal in area]

Subtract Area (ΔDOC) from both side

Area (ΔADC) – Area (ΔDOC) = Area (ΔBDC) – Area (ΔDOC)

Area (ΔAOD) = Area (ΔBOC)

Hence proved.

Step-by-step explanation:

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Answer 2

Answer:

the digonal of rectangle equal or congruent

90° is the ANS

ar(triangleBDC) = 90°

Step-by-step explanation:

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