ABCD is a rectangle and BD is one of its diagonals.if ar(abd)=8cm square,find ar(bcd).
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Answered by
77
In Δabd and Δbdc,
BD is common
∠DAB =∠BCD=90°
AB=DC (opp. sides in a rectangle)
by RHS congruency,
Δabd is congruent to Δbcd
Then their areas are equal so,ar(abd)=ar(bcd)
therefore ar(bcd)=8 cm sq.
BD is common
∠DAB =∠BCD=90°
AB=DC (opp. sides in a rectangle)
by RHS congruency,
Δabd is congruent to Δbcd
Then their areas are equal so,ar(abd)=ar(bcd)
therefore ar(bcd)=8 cm sq.
Answered by
9
The ar of BCD = 8cm this is the answer
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