ABCD is a rectangle and BD is one of its diagonals.if ar(abd)=8cm square,find ar(bcd).
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In triangle ABD and BCD
BD=BD(diagonals)
BC=AD(opp. sides of rectangle are equal)
AB=DC(opp. sides of rectangle are equal)
therefore triange ABD is congruent to triangle BCD
Hence ar(ABD)=ar(BCD)
Area of triangle BCD is 8 sq.cm
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