ABCD is a rectangle and diagonals intersect at O. If angle AOB= 118 find angle ABO
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Step-by-step explanation:
Given=ABCD is a rectangle, diagonals intersect at O
Find=<ABO
solve=<AOB=118°
<AOB+<OBA+<OAB=180° (sum of angle of∆)
118°+<OBA+<OBA=180° (<OBA=<OBA, because
opposite side are
equal)
2<OBA=180°-118°
<OBA = 62°\2
<OBA=31°
<AOB is 31°
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