Math, asked by sureshhhhhhh33333, 1 day ago

ABCD is a rectangle and EDGF and BJIH are one square. If AD = 20cm, AB = 9cm, ED = 7cm, BJ = 8cm, what is the area of ​​the entire area?

Answers

Answered by Anonymous
2

Answer:

295 cm^2

Step-by-step explanation:

ABCD is a rectangle, thus all the angles are 90°

EDGF and BJIH are squares, thus all the angles are 90°

possible diagram is mentioned in the image.

Area of rectangle ABCD = length × breadth

= 20 × 9 = 180 cm^2

Area of square EDGF = side × side = 7 × 7 = 49 cm ^2

Area of square BJIH = side × side = 8 × 8 = 64 cm ^2

entire area = ar(ABCD) + ar(EDGF) + ar(BJIH)

= 180+49+64 = 295 cm^2

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