ABCD is a rectangle and EFGH is a parallelogram using the measurements given in the figure, what is the length d of the segment that is perpendicular to HE and FG?
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Answer:
HE = 5 cm and FG = 5 cm
Step-by-step explanation:
in AHE,
(HE)^2 = (AE)^2 + (AH)^2
(HE)^2 = (4)^2 + (3)^2
(HE) ^2 = 16 + 9
(HE)^2 = 25
HE = 5
in CGF,
(FG)^2 = (CF)^2 + (CG)^2
(FG)^2 = (3)^2 + (4)^2
(FG)^2 = 9 + 16
(FG)^2 = 25
FG = 5
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