Question

abcd is a rectangle and o is any point in its interior. Prove that area of AOD + area of BOC =area of AOB +area of COD​

Answer 1

Answer:

Step-by-step explanation:

Area of Triangle AOB is congruent to area of triangle AOD by SSS rule because AB=AD (Opp sides of parallelogram)

AO=BO=DO (diagonals are equal and bisected each other)so AO=AO

BO=DO

Similarly triangle COD will be equal to triangle BOC (by sss rule again)

Since triangles AOB=AOD =COD=BOC

so proved

Answer 2

Answer:

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