Question

ABCD is a rectangle and P is a point inside it such that AP = 33 , BP = 16 , DP= 63 . find CP​

Answer 1

QUESTION⤵️

ABCD is a rectangle and P is a point inside it such that AP = 33 , BP = 16 , DP= 63 . find CP

ANSWER⤵️

GIVEN THAT:::-

p is a point inside rectangle ABCD

AP = 33

BP = 16

DP = 63

TO FIND:::-

CP

LET'S DO IT:::-

In rectangle, the diagonals are equal.

${DP}^{2} + {PB}^{2} = {AP}^{2} + {CP\: }^{2}$

${63}^{2} + {16}^{2} = {33}^{2} + {CP}^{2}$

$3969 + 256 = 1089 + {CP}^{2}$

${CP}^{2} = 3136$

$: \longrightarrow \pink{56}$

$\purple{BE \: \: BRÃÎÑLY❥}$

ANNYONG ARMY