Question

ABCD is a rectangle and P is the midpoint of AB. DP is produced to meet CB at Q prove that area of rectangle ABCD equal to area of triangle DQC.
from chapter theorems on area
Pls answer fast today is my exam

Answer 1

in tri dqc and tri pob
ang pbq =ang dcq =90 ( given )
ang q =commen
therefor the tri are similar by aa
qb =bc
qb=1/2qc
dc=cb=1/2 qc ×dc
dc×cb=qb×dc