Question

ABCD is a rectangle and point P is such that PA = 5 cm, PC = 4 cm and PD = 3 cm, find the value of PB.​

Answer 1

Step-by-step explanation:

Given PA=3 cm

PC=3

2

cm

PD=5 cm

AC=PA+PC

AC=PA+PC

=3+3

2

=3(1+

3

)

=3(1+1.414)

=3(2.414)

AC=7.242

We know that in rectangle

AC=BD

AC=PD+PB

7.242=5+PB

PB=7.242−5

PB=2.242

PB=2.242 cm