Abcd is a rectangle angle back=32 degree. Determine angle DBC.
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Answered by
168
In ΔDBC
∠BAC = ∠BDC
as ∠BDC= 32
The sum of interior angles of triangle = 180
∠BDC + ∠C + ∠B= 180
32 + 90 + ∠DBC= 180
∠DBC= 58
∠BAC = ∠BDC
as ∠BDC= 32
The sum of interior angles of triangle = 180
∠BDC + ∠C + ∠B= 180
32 + 90 + ∠DBC= 180
∠DBC= 58
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