Question

ABCD is a rectangle calculate the area of the shaded portion

Answer 1

ar(shaded region)=ar (Rectangle)-ar(right angled trapezium)
=(12*16)-(1/2*(8+4)*6)
=192-36=156 cm^2..

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Answer 2

Given length 'l' of rectangle = 16 cm

Breadth 'b' = 12 cm

Dimensions of Trapezium

Side 'a' = 4 cm

Side 'a' = 4 cmSide 'b' = 8 cm

Side 'a' = 4 cmSide 'b' = 8 cmSide 'c' = 6 cm

Therefore, Area of shaded region = Area of rectangle - Area of trapezium

$= l \: \times b \: - \frac{1}{2} \: h(a + b)$

$= 16 \times 12 - \frac{1}{2} \times 6(4 + 8)$

$= 192 - 3(12)$

$= 192 - 36$

$= 156 \: {cm}^{2}$