ABCD is a rectangle diagonal AC divide c in the ratio 2 : 3 find ACB and ACD
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Answered by
3
let the ratio be x
so 2x+ 3x= 90°
5x= 90°
x= 90/5
=18 answer
so 2x+ 3x= 90°
5x= 90°
x= 90/5
=18 answer
Answered by
3
Lacb=54
Lacd=36
this is the answer make it the brainliest
exp
angle dcb is 90 the ratio it is divided is 2:3 so, let the common multiple be x
therefore
2x+3x=90
5x=90
x=90/5
x=18
therefore angle acb =2x=2*18=36
angle acd =3x=3*18=54
and 54+36=90
Lacd=36
this is the answer make it the brainliest
exp
angle dcb is 90 the ratio it is divided is 2:3 so, let the common multiple be x
therefore
2x+3x=90
5x=90
x=90/5
x=18
therefore angle acb =2x=2*18=36
angle acd =3x=3*18=54
and 54+36=90
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