ABCD is a rectangle .E is the midpoint of AB. prove that DEC is an isosceles triangle.
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Given : ABCD is a rectangle.
E is the mid point of side AB.
To prove : Triangle DEC is isosceles.
Proof : In triangles ADE and BCE
AD = BC (opp sides of rectangle)
AE = BE (E is the mid point)
Angles DAE and CBE are 90° (all angles in a rectangle are 90°)
therefore triangles DAE and CBE are congruent (SAS congruence rule)
DE = CE (by CPCT)
two sides are equal so triangle DEC is isosceles...
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