Question

ABCD is a rectangle. E is the midpoint of AB. Prove that ΔDEC is an isosceles triangle. (HINT : Prove using SAS, ΔAED = ΔBEC ).​

Answer 1

Answer:

in ΔAED and ΔBEC

AE=EB ( given)

angleA =angleB ( each 90°)

AD=BC ( SIDES OF rectangle)

. ° . ΔAED = ΔBEC ( by SAS)

DE= CE ( BY CPCT)

Hence ️DEC is an isosceles triangle