Question

ABCD is a rectangle E is the midpoint of AB prove that ∆ DEC is an isosceles triangles ​

Answer 1

Step-by-step explanation:

In triangle ABE and DCE

AB=DC(OPP. SIDES OF SQUARE)

AE=DE(E IS MIDPT.OF AD)

Angle BAE= angle CDE(ANGLES OF SQUARE ARE EQUAL)

TRIANGLE ABE IS CONGRUENT TO TRIANGLE DCE BY SAS CONGRUENCY

BE=CE(CPCT)

AS TWO SIDES OF A TRIANGLE ARE EQUAL THE TRIANGLE BED IS AN ISOSCELES TRIANGLE

Answer 2

Step-by-step explanation:

I have mentioned the area for congruency. As , if the area is same the measure of the side will also be same in that way we can say that the two triangles are in SAS or SSS . Hope it helps