Question

ABCD is a rectangle, F is the midpoint of AB, and BC is extended to X, and BC = 145 cm. What is the length of BX (in cm) for which the area of triangle AFX is 58 of the area of the rectangle ABCD?


6 7 8
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Answer 1

Step-by-step explanation:

Given that E and F are mid-points of BC and AD respectively.

ar(□ABFE)=

2

1

ar(□ABCD)[∵ E and F are mid points of BC and AD respectively]

ar(△GAB)=

2

1

ar(□ABFE)[∵ Area of triangle is half of area of rectangle on the same base and between the same parallels]

=

2

1

×

2

1

ar(□ABCD)

=

4

1

ar(□ABCD)