Math, asked by arshdeepbajwa7738, 1 year ago

ABCD IS A rectangle .find value of X and Y
DC= x+y
CB= x-y
Da=14cm
Ab=30

Answers

Answered by oliviagunda
0

Answer:

x = 22 , y = 8

Step-by-step explanation:

dc = ab = 30

x + y = 30 .............(1)

bc = ad = 14

x - y = 14 ..............(2)

(1) + (2)

2x = 44

x = 22

y = 30 - 22 = 8

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Answered by TransitionState
0

Answer: 8 cm

Step-by-step explanation:

ABCD IS A rectangle .find value of X and Y DC= x+y CB= x-y Da=14cm Ab=30

Given: rectangle ABCD, DC= x+y, CB= x-y Da=14cm Ab=30

Solution:

In rectangle ABCD, AB is parallel and congruent to DC because the opposite sides of the rectangle is parallel and congruent. Therefore,

AB = DC or DC = AB

DC = AB Substitute.

x + y = 30  Equation (1)

In rectangle ABCD, CB is parallel and congruent to DA because the opposite sides of the rectangle is parallel and congruent. Therefore,

CB = DA Substitute.

x - y = 14  Equation (2)

Then, apply elimination in solving linear equations with two variables using the two equations.

x + y = 30  Equation (1)

x - y = 14  Equation (2)  Add similar terms.

2x + 0 = 44

     2x = 44  Divide both sides by 2 applying Division Property of Equality

  2x/2 = 44/2  Applying Division Property of Equality

       x = 22 cm

Substitute the value of x to any of the two equations to find the value of y.

x + y = 30  Equation (1)

22 + y = 30

22 + y + (– 22) = 30 + (– 22) Applying Addition Property of Equality by adding -22 to both sides.

     22 – 22 + y = 30 – 22

                0 + y = 8

                      y = 8 cm

Answer: The value of x is 22 cm and the value of y is 8 cm.

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