Question

abcd is a rectangle if ab =5 cm and ac= 13 cm find the perimeter of abcd

Answer 1

$\underline{\boxed{Hey \:mate....}}$
here is your answer

In rectangle ABCD,
ab=base =5 cm
ac=diagonal =13 cm

by pytgagoras theorem

in ∆ abc
ac2=ab2+ bc2
169=25+bc2
144=bc2
bc=12

p of ABCD =2(12+5)
=2×17
=34 cm

Answer 2

Given,

The rectangle abcd

ab = 5cm

ac =13cm

To Find,

The perimeter of the rectangle abcd.

Solution,

abcd is a rectangle.

side ab = 5cm

ac = 13cm (diagonal of the rectangle)

Using Pythagoras theorem

ac² = ab²+bc²

ac =13cm

ab = 5cm

13² = 5² + bc²

169= 25 +bc²

bc² =169 -25

bc² = 144

bc =√144

12cm

Rectangle abcd's two sides

ab= 5cm

bc = 12cm

Therefore, the perimeter of the rectangle

2(l+w),

l= length

w = width

2(5+12)

2*17 = 34cm

The perimeter of the rectangle abcd which has one side of 5cm and a diagonal of 13cm is 34cm.