Question

ABCD is a rectangle if angleCEB:angleECB = 3:2, find the measure of angleECB, angleAEC​

Answer 1

Step-by-step explanation:

ABCD is a rectangle

So, <EBC = 90°

Now ,let <CEB = 3x

so <ECB = 2x

now, <ECB +< CEB =90°

=> 2x +3x =90°

=>5x =90°

=> x = 90°/5

= 18°

<ECB = 2×18°

=36⁰

Again ABCD is a rectangle

so AB|| CD and EF is a transversal

So, <AEC = <DCF=126⁰( corresponding angle)

I e. <AEC = 126⁰