ABCD is a rectangle. If N, 0 and M are the midpoint of
AB, BD and CD respectively, then find:
a) Area of ∆COD
b) Area of (CBNO) : Area of (ABCD)
Pls write clear steps and then send
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Step-by-step explanation:
If AB=30 cm then,DC =30cm soDM=15 and MC=15
If ON=10cm then,OM=10cm
Firstly, we will find the area of triangle MOD=1/2*B*H=1/2*15*10=75sq.cm
Since,triangle MOD=COM so area of tri. COM=75
Therefore Area of triangle COD=(75+75)cm=150sq.cm.
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