Question

ABCD is a rectangle.If the area of a rectangle APB=30.What is the area of triangle ACB?What is the area of rectangle?​

Answer 1

Step-by-step explanation:

In right angle triangle ABP,

Sin theta = opposite/Hypotenuse

Hence,

sin 30 degree = 50/AP

1/2=50/AP

AP=50*2

AP= 100 cm

Also, Similaraly In right angle triangle ADQ

sin 30 degree = 20/AQ

AQ = 40 cm