ABCD is a rectangle if unshaded area is 48 cm2 and AB:BC=3:2. find the perimeter of rectangle. Shaded region: Triangle BEC and Triangle AED
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HEY BUDDY .....
HERE IS UR ANSWER ........
AREA OF SHADED AREA = AREA OF UNSHADED AREA = 48cm^2
LET THE RATIO BE 3x & 2x .
SO, AREA OF RECTANGLE = 2×48 = 96cm^2. [ BECAUSE ALL TRIANGLE IN A RECTANGLE HAVE EQUAL AREA ]
AGAIN, AREA OF RECTANGLE = (3x)×(2x) = 96cm^2 =] 6x^2 = 96
=]. x^2 = 96/6 = 16
=]. x = 4cm
SO, BREADTH AB = 3×4 = 12 cm
LENGTH BC = 2×4 = 8cm
SO, PERIMETER OF RECTANGLE = 2(l+b)
= 2(12+8) = 2×20 = 40cm
HOPE U UNDERSTAND BRO ✨✨
HERE IS UR ANSWER ........
AREA OF SHADED AREA = AREA OF UNSHADED AREA = 48cm^2
LET THE RATIO BE 3x & 2x .
SO, AREA OF RECTANGLE = 2×48 = 96cm^2. [ BECAUSE ALL TRIANGLE IN A RECTANGLE HAVE EQUAL AREA ]
AGAIN, AREA OF RECTANGLE = (3x)×(2x) = 96cm^2 =] 6x^2 = 96
=]. x^2 = 96/6 = 16
=]. x = 4cm
SO, BREADTH AB = 3×4 = 12 cm
LENGTH BC = 2×4 = 8cm
SO, PERIMETER OF RECTANGLE = 2(l+b)
= 2(12+8) = 2×20 = 40cm
HOPE U UNDERSTAND BRO ✨✨
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6
Answer:
40 cm^2...
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