Math, asked by ajitkumarcoolboy2, 7 months ago

ABCD is a rectangle in which AB = 12 cm and AC = 20 cm .PQRS is another rectangle , wherein PQ = 7 cm and PR = 25 cm .Which rectangle has larger perimeter ​

Answers

Answered by ravindersg1978
2

Answers

PERIMETER OF RECTANGLE ABCD= 2(L + B)

                                                  = 2 X 12 + 20 CM

                                                 =  2 X 32 CM

                                                 =  64 CM

THERFORE PERIMETER OF RECTANGLE ABCD= 64 CM

NOW,

PERIMETER OF RECTANGLE PQRS= 2(L + B)

                                                              = 2 X 7 + 25 CM

                                                                =  2 X 32 CM

                                                                =  64 CM

THERE FORE PERIMETER OF RECTANGLE PQRS = 64 CM

THUS ,THE PERIMETER OF BOTH THE RECTANGLES ARE EQUAL

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