Question

ABCD is a rectangle in which AB = 28 cm and AC = 35 cm. Find the perimeter of the rectangle ABCD.
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Answer 1

Answer:

98cm

Step-by-step explanation:

(AC)^2=(AB)^2+(BC)^2

(35)^2=(28)^2+(BC)^2

1225=784+(BC)^2

(BC)^2=1225-784

(BC)^2=441

(BC)^2=(21)^2

BC=21cm

So, perimeter of the rectangle = 2(l+b)

=2(28+21)

=2×49

=98cm