ABCD is a rectangle in which AB/BC = 4/3 The bisector of Z meets AB is E. If AB = 1 cm AE
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In △AFE and △BFC,
∠AFE=∠BFC (Common angle)
∠AEF=∠BCF (Corresponding angles of parallel lines)
∠FAE=∠CBF (Corresponding angles of parallel lines)
Thus, △AFE∼△CFB (AAA rule)
Hence, BFAF=BCAE
AF+ABAF=BCAE
8+128=BC4
BC=84×20
BC=10 cm
Perimeter of parallelogram = AB+BC+BC+AD
Perimeter of parallelogram = 2(AB+BC)
Perimeter of parallelogram = 2(12+10) (Opposite sides are equal)
Perimeter of parallelogram = 44 cm
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Answer:5/8 cm
Step-by-step explanation:
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