Question

ABCD is a rectangle in which AB/BC = 4/3 The bisector of Z meets AB is E. If AB = 1 cm AE
=​

Answer 1

In △AFE and △BFC,

∠AFE=∠BFC (Common angle)

∠AEF=∠BCF (Corresponding angles of parallel lines)

∠FAE=∠CBF (Corresponding angles of parallel lines)

Thus, △AFE∼△CFB (AAA rule)

Hence, BFAF=BCAE

AF+ABAF=BCAE

8+128=BC4

BC=84×20

BC=10 cm

Perimeter of parallelogram = AB+BC+BC+AD 

Perimeter of parallelogram = 2(AB+BC) 

Perimeter of parallelogram = 2(12+10)  (Opposite sides are equal) 

Perimeter of parallelogram = 44 cm

Answer 2

Answer:5/8 cm

Step-by-step explanation: