ABCD is a rectangle in which diagonal AC bisects ∠A as well as ∠C. Show that: (i)ABCD is a square (ii) Diagonal BD bisects ∠B as well as ∠D.
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-ABCD is a rectangle in which diagonal AC bisects angle A as well as angle C .
◽To proove :-1) ABCD is a square .
◽2)diagonal BD bisects angle B as well as angle d .
◽PROOF:-1)Since AC bisects angle A
as well as angle C .
◽To prove :-1) ABCD is a square .
◽2)diagonal BD bisects angle B as well as angle d .
◽PROOF:-1)Since AC bisects angle A as well as angle C in the rectangle ABCD .
◽angle 1=angle 2 =angle 3 =angle 4 (each =90/2=45 degree)
◽In triangle ,angle 2 = angle 4
◽=AD=CD ( Sides opposite to equal angles)
◽Thus, the rectangle ABCD is a square .
◽2)In a square ,diagonals bisect the angles .
◽So, BD bisects angle B as well as angle D .
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Plz refer to the pic given
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