ABCD is a rectangle in which diagonal AC bisects angle A as well as angle C show that
ABCD is a square
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Answered by
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let ABCD be a rectangle.
and AC be a diagonal.
here,
angle DAB = angle DCB. ( opp. angle of rectangle)
1/2angle DAB = 1/2 angle DCB
angle CAB = angle ACB
so,
AB=CB. (. sides of iso. triangle)
so, AB= DC and AD=BC. ( opp. sides of rectangle)
so, AB=BC=CD=DA
hence, ABCD is a square.
☣☣☣☣☣☣☣☣☣☣☣☣☣☣☣☣☣☣☣☣☣☣☣☣☣☣
hope you are satisfied with my answer
from brainly benefactor
Amaytripathi19
here's your answer looking for
☣☣☣☣☣☣☣☣☣☣☣☣☣☣☣☣☣☣☣☣☣☣☣☣☣☣☣☣☣
let ABCD be a rectangle.
and AC be a diagonal.
here,
angle DAB = angle DCB. ( opp. angle of rectangle)
1/2angle DAB = 1/2 angle DCB
angle CAB = angle ACB
so,
AB=CB. (. sides of iso. triangle)
so, AB= DC and AD=BC. ( opp. sides of rectangle)
so, AB=BC=CD=DA
hence, ABCD is a square.
☣☣☣☣☣☣☣☣☣☣☣☣☣☣☣☣☣☣☣☣☣☣☣☣☣☣
hope you are satisfied with my answer
from brainly benefactor
Amaytripathi19
Answered by
7
Answer:
hope it will help you please mark me as brainliest please please please please
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