ABCD is a rectangle in which diagonal AC bisects angle A as well as angle C . show that (1) ABCD is a square .
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Hi friend ✨✨✨
Given;- -ABCD is a rectangle in which diagonal AC bisects angle A as well as angle C .
To prove :-1) ABCD is a square .
2)diagonal BD bisects angle B as well as angle d .
PROOF:-1)Since AC bisects angle A as well as angle C in the rectangle ABCD .
angle 1=angle 2 =angle 3 =angle 4 (each =90/2=45 degree)
In triangle ,angle 2 = angle 4
=AD=CD ( Sides opposite to equal angles)
Thus, the rectangle ABCD is a square .
2)In a square ,diagonals bisect the angles .
So, BD bisects angle B as well as angle D .
Hope helps!!
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