Math, asked by mimansha13, 1 year ago

ABCD is a rectangle in which diagonal AC bisects angle A as well as angle C . show that (1) ABCD is a square .


pavanmeena16200366: MAKR AS BRAINLIEST

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Answered by pavanmeena16200366
12

Answer:

Hi friend ✨✨✨


Given;- -ABCD is a rectangle in which diagonal AC bisects angle A as well as angle C .


To prove :-1) ABCD is a square .


2)diagonal BD bisects angle B as well as angle d .


PROOF:-1)Since AC bisects angle A as well as angle C in the rectangle ABCD .


angle 1=angle 2 =angle 3 =angle 4 (each =90/2=45 degree)


In triangle ,angle 2 = angle 4


=AD=CD ( Sides opposite to equal angles)


Thus, the rectangle ABCD is a square .


2)In a square ,diagonals bisect the angles .


So, BD bisects angle B as well as angle D .


Hope helps!!




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