ABCD is a rectangle in which diagonal AC bisects Z A as well as < C. Show that (1) ABCD is a square (ii) diagonal BD bisects < B as well as Z D. what is the answer
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Answer:
In △ABC,
∠CAB=∠BCA , therefore
BC=AB →(4)[sides opposite to equal angles]
But BC=AD & AB=DC→(5) [Opposite sides of rectangle]
Therefore from (4)& (5),
AB=BC=CD=AD
Hence, ABCD is a square.
(ii) ABCD is a square and we know that diagonals of a square bisect its
angles.
Hence, BD bisects ∠B as well as ∠D
Step-by-step explanation:
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