ABCD is a rectangle in which DP and BQ are perpendicular from d and b respectively on diagonal AC show that--
(i) ∆ADP=∆CBQ
(ii) angle angle ADP is equals to angle CBQ
(iii) DP=BQ
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60
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1) ,2)∆ADP=∆CBQ (R.H.S)
3) DP=BQ (C.P.C.Ts)
please refer to the attachment...
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