Question

abcd is a rectangle in which dp and bq are perpendiculars from d and b respectively on diagonal ac. show that (1) triangle adp congruence triangle cbq and (2) angle adp =angle cbq and (3) dp=bq

Answer 1

Step-by-step explanation:

1. Triangle ADP and triangle CBQ

• angle DAP=angle BCQ(alternate int. angles)
• angle DPA =angle BQC each 90°(given)
• side AD=side BC( opposite side of rectangle are equal)

therefore Triangle ADP is congruent to triangle CBQ by AAS congruence condition

2. angle adp = angle cbq ( c. p. c. t)

3. dp=bq(c. p. c. t.)

Hope u like my answer

Answer 2

Answer:

above answer is helpful