ABCD is a rectangle in which JCAC) pokyny Mis the point of intersection of the diagonal , what is I (AM) :P ) ?
Answers
Answer:
672 centimetres square
Step-by-step explanation:
[Note : refer the figure as shown in the attachment ]
{\textbf{\large{Step-by-step explanation:}}}Step-by-step explanation:
⬛ABCD is a rectangle ,
As from the properties of rectangle
Diagonal AC = Diagonal BD
∴ AO = BO
⟹ (6x+ 1) = (8x-7)
⟹ 6x - 8x = - 7 - 1
⟹ - 2x = - 8
⟹ x = - 8 / - 2
∴ The value of x is
\boxed{\textbf{\large{x = 4}}}
x = 4
_________________________________
Diagonal AC = 2(AO )
AO = ((6( 4 )+ 1))
= ( 6 (4) + 1)
= ( 24 + 1)
= 25
diagonal AC = diagonal BD =
= 25 x 2 = 50
let us suppose A triangle ABC
/_ ABC = 90°
therefor, by Pythagoras theorem
( AC )^2 = ( AB) ^2 + ( BC) ^2
(50)^2 = ( AB )^2 + ( 48 )^2
2500 = ( AB) ^2 + ( 2304 )
2500 - 2304 = ( AB) ^2
AB = √ 196
\boxed{\textbf{\large{AB = 14 cm }}}
AB = 14 cm
__________________________________
Now, find the perimeter of ⬛ABCD
As we know, the formula to find the perimeter of rectangle
★perimeter of rectangle = 2 ( l + b)
where length is BC and breadth is AB
therefor ,
perimeter of rectangle ABCD
= 2 ( ( BC ) + ( AB))
= 2 ((48 + 1 4 )
= 2 ( 62 )
\boxed{\textbf{\large{124 cm }}}
124 cm
Therefor, perimeter of rectangle ABCD is 124 cm
__________________________________
Now,
★ Area of rectangle = l x b
Area of rectangle ABCD
= ((BC) x (AB))
= ( 48 x 14 )
\boxed{\textbf{\large{672 cmSquare}}}
672 cmSquare