ABCD is a rectangle. Its diagonals meet at O.Find 'x',if OA=2x +4 and OD =3x + 1. Also find AD
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ABCD Is A Rectangle
So, It's Diagonal Will Be Equal
And ATQ
OA = 2x+4 and OD = 3x+1
OA=OD [Both are the Diagonal Having Same MidPoint ]
2x+4 = 3x+1
2x-3x = 1-4
-x = -3
X = 3
Now Put this Value In OA and OD
For OA
2x+4
= 2×3+4
= 6+4
= 10
Now for OD
3x+1
=3×3+1
= 9+1
= 10
Now Both are the Diagonal having same MidPoint.
OA+OD
10+10
= 20
AD = 20 Ans
So, It's Diagonal Will Be Equal
And ATQ
OA = 2x+4 and OD = 3x+1
OA=OD [Both are the Diagonal Having Same MidPoint ]
2x+4 = 3x+1
2x-3x = 1-4
-x = -3
X = 3
Now Put this Value In OA and OD
For OA
2x+4
= 2×3+4
= 6+4
= 10
Now for OD
3x+1
=3×3+1
= 9+1
= 10
Now Both are the Diagonal having same MidPoint.
OA+OD
10+10
= 20
AD = 20 Ans
Akv2:
Ad = 20 How ???
@akv2 Pls check the process bro
Ad = Ao + Bo How ???
bro that's OD not BO
check once
Ad = Ao + Od How ???
draw a rectangle and give Name ABCD and draw diagonal from AD and BC
and the mid point is O
Ooo thanks
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